Limiting Reagents Explained
The limiting reagent is the reactant that runs out first. It controls how much product can form — the theoretical yield — no matter how much of the other reactants you have.
The method
- Balance the equation so the mole ratios are correct.
- Convert each given reactant to moles with n = m ÷ M.
- Work out how much product each reactant could make on its own, using its mole ratio to the product.
- The smaller answer is the theoretical yield, and the reactant that produced it is the limiting reagent. The other reactant is in excess.
Worked example
N₂ + 3 H₂ → 2 NH₃. Mix 28.0 g N₂ and 6.00 g H₂.
n(N₂) = 28.0 ÷ 28.02 = 1.00 mol → 2.00 mol NH₃
n(H₂) = 6.00 ÷ 2.016 = 2.98 mol → 2.98 × (2÷3) = 1.98 mol NH₃
n(H₂) = 6.00 ÷ 2.016 = 2.98 mol → 2.98 × (2÷3) = 1.98 mol NH₃
Hydrogen makes less ammonia, so H₂ is the limiting reagent and the theoretical yield is 1.98 mol × 17.03 g/mol ≈ 33.8 g NH₃.
Percent yield
Once you have the theoretical yield, percent yield compares it to what was actually obtained:
% yield = (actual yield ÷ theoretical yield) × 100%
Find the molar masses you need with the Molar Mass Calculator, and review the general method in How to Approach Stoichiometry.
More limiting-reagent practice
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The General Chemistry Workbook has worked limiting-reagent and percent-yield problems with a full answer key.