How to Approach Stoichiometry
Almost every stoichiometry problem follows the same path: get to moles, use the balanced equation to cross over to the substance you want, then get back to the units the question asks for.
The four-step road map
- Balance the equation. The coefficients are the mole ratios you will use, so the equation has to be balanced first.
- Convert the known amount to moles. From a mass, use n = m ÷ M. From a gas volume or a solution, use the relevant relationship (PV = nRT, or n = M × V).
- Apply the mole ratio. Multiply by the ratio of coefficients from the balanced equation to get moles of the substance you want.
- Convert to the requested units. Moles back to grams (m = n × M), to volume, or to particles (N = n × N_A), as needed.
Worked example
How many grams of FeCl₃ form when 38.5 g of Cl₂ reacts with excess iron, given 2 Fe + 3 Cl₂ → 2 FeCl₃?
n(Cl₂) = 38.5 ÷ 70.90 = 0.543 mol
Mole ratio Cl₂ → FeCl₃ is 2 : 3, so n(FeCl₃) = 0.543 × (2 ÷ 3) = 0.362 mol. Then m = 0.362 × 162.20 = 58.7 g of FeCl₃.
Common pitfalls
- Forgetting to balance first, so the mole ratio is wrong.
- Using the mass ratio instead of the mole ratio — only moles carry the coefficient ratio.
- Skipping unit conversions, especially mL to L and °C to K.
Start by finding molar masses with the Molar Mass Calculator, then handle solutions with the Molarity Calculator. When two reactants are given, see Limiting Reagents Explained.
Practice with worked solutions
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The General Chemistry Workbook has a full stoichiometry chapter with worked examples and an answer key.