Gases & Thermo

Calorimetry Calculator

Solve q = mcΔT for heat, mass, specific heat or temperature change. Pick a substance from the presets to fill in its specific heat automatically.

q = mcΔT

Choose what to solve for

g
J·g⁻¹·°C⁻¹ — presets from the workbook reference table.
°C
Positive if it warmed up, negative if it cooled.
result
Working

    Specific heats from the workbook reference (water 4.184 J·g⁻¹·°C⁻¹). Methodology & sources →

    Thermochemistry homework? The General Chemistry Workbook covers calorimetry, Hess's law and enthalpies of formation with worked examples.As an Amazon Associate we earn from qualifying purchases.

    View on Amazon →

    Heat, Mass and Temperature

    q = m · c · ΔT  where ΔT = T_final − T_initial

    q is the heat transferred. A positive value means the substance absorbed heat (it warmed up); a negative value means it released heat. The specific heat c tells you how much energy one gram needs to change by one degree — water's high value (4.184 J·g⁻¹·°C⁻¹) is why it resists temperature change. In coffee-cup calorimetry the heat of reaction is the opposite of the heat gained by the solution: q_rxn = −q_solution.

    Worked Example — Heat of Solution from Calorimetry Data

    Question: 0.205 g of KOH is dissolved in 55.9 g of water in a coffee-cup calorimeter. The temperature rises from 23.5°C to 24.4°C. Find ΔHsoln in kJ/mol. Assume cp = 4.184 J g⁻¹ °C⁻¹.

    Step 1 — heat absorbed by the solution: qsoln = mcΔT = (55.9 + 0.205) × 4.184 × (24.4 − 23.5) = 210.9 J

    Step 2 — heat of reaction: qrxn = −qsoln = −210.9 J (the dissolution releases heat into the solution)

    Step 3 — moles of KOH (M = 56.11 g/mol): n = 0.205 ÷ 56.11 = 3.65 × 10⁻³ mol

    Step 4 — molar enthalpy: ΔHsoln = qrxn ÷ n = −210.9 ÷ 3.65×10⁻³ = −57,700 J/mol = −57.7 kJ/mol

    Answer: ΔHsoln = −57.7 kJ/mol (exothermic, since the temperature rose).

    Common Mistakes

    • Sign convention. A temperature rise means the reaction released heat into the solution — so qrxn is negative (exothermic), even though qsoln (heat gained by the solution) is positive. They are equal in size and opposite in sign.
    • Which mass to use. Use the total mass of the resulting solution (solute + solvent) in q = mcΔT, not just the solvent — though for dilute solutions the solute mass is often small enough to be a minor correction.
    • J vs. kJ. q = mcΔT gives joules when cp is in J g⁻¹°C⁻¹. Divide by 1000 to report ΔH in kJ/mol, and divide by n after converting, or be consistent throughout.

    Frequently Asked Questions

    Heat (q) equals mass (m) × specific heat (c) × temperature change (ΔT). Positive q is heat absorbed, negative q is heat released.

    4.184 J·g⁻¹·°C⁻¹. Presets for ice, steam, aluminium, iron, copper and gold are in the dropdown.

    Energy is conserved: heat that leaves the chemical reaction (qrxn, if exothermic) is the same heat that enters the surrounding solution (qsoln). Since one is heat leaving and the other is heat arriving, they have equal magnitude but opposite sign — this is the basic assumption behind calorimetry.

    For dilute aqueous solutions, cₐ of pure water (4.184 J g⁻¹ °C⁻¹) is the standard approximation, since water dominates the mass and heat capacity of the mixture. For concentrated solutions or non-aqueous solvents, a different, measured specific heat should be used if known.

    Study Guides

    Chemistry Guides & Worked Explanations

    Plain-language explanations written for high school and first-year college students — each one links through to the matching calculator.

    Stoichiometry
    Solutions & Acids
    Gases, Thermo & Reference